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0.25m^2+2m-5=0
a = 0.25; b = 2; c = -5;
Δ = b2-4ac
Δ = 22-4·0.25·(-5)
Δ = 9
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{9}=3$$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(2)-3}{2*0.25}=\frac{-5}{0.5} =-10 $$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(2)+3}{2*0.25}=\frac{1}{0.5} =2 $
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